Re: [Quickfix-developers] ctrl-c , sleep and a clean shutdown

[Oren M. <or...@qu...>]

It wouldn't.  The reason this was done is because it turns out doing=20
handling this in a portable way (i.e. works in unix and windows), turns=20=

out to be not trivial.  I didn't want to clutter up the sample code=20
with that sort of nonsense so I just took the easy way out.  You are=20
correct in noting that this will not do a clean exit, and will in fact=20=

result in a SIG_INT which terminates the application.  If you look at=20
the java example, you will see that it waits for a keypress and then=20
does do a proper exit.  If you want to do a clean exit on Ctrl-C, you=20
will have to set up a signal handler for your application.

--oren

On Jun 4, 2004, at 8:06 PM, Clark Sims wrote:

> In the file executor.cpp I see the following code:
> =A0
>
> void wait()
> {
> =A0 std::cout << "Type Ctrl-C to quit" << std::endl;
> =A0 while(true)
> =A0 {
> =A0=A0=A0 FIX::process_sleep(1);
> =A0 }
> }
>
> and this is called from
>
>  =A0
>
>
> =A0=A0=A0 acceptor.start();
> =A0=A0=A0 wait();
> =A0=A0=A0 acceptor.stop();
> =A0=A0=A0 return 0;
>
> =A0
>
> acceptor.stop(), must be the function that cleans up before a =
shutdown.
>
> =A0
>
> I don't understand how ctrl-c causes wait to return. I went through=20
> the code for process_sleep, and no call to signal, is made. Nor is=20
> there a call to signal anywhere else. It looks to me that typing=20
> ctrl-c would cause the program to shutdown immediately, and that=20
> acceptor.stop, would never be called.
>
> =A0
>
> So my question is, how can ctrl-c cause this program to shutdown in a=20=

> clean way?
>
> =A0
>
> Thanks in Advance,
>
> =A0
>
> Clark Sims
>
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