Re: [q-lang-users] [Chicken-users] Re: IEEE float arithmetic

[Albert G. <Dr....@t-...>]

John Cowan wrote:
> The expression "f != 0.0 && f == f + f" will work, I think.
> 0.0 and NaN are rejected by the left side of "&&", and all
> other finite values by the right side.

Ok, I'll fix that, thanks.

-- 
Dr. Albert Gr"af
Dept. of Music-Informatics, University of Mainz, Germany
Email:  Dr....@t-..., ag...@mu...
WWW:    http://www.musikinformatik.uni-mainz.de/ag