Re: [q-lang-users] Q 7.2 RC1 Issue 3: IEEE floats

[John C. <co...@cc...>]

Albert Graef scripsit:

> Hmm, I guess that should actually be:
> 
> 	return (f - f != f && f + f == f);
> 
> We shouldn't forget that 0.0 is idempotent for (+), too. ;-)

Oops yet again.

Still f == f + 1 should still work; no finite value will work there,
and neither will nan, because although nan + 1 is nan, it is false
that nan == nan.

-- 
John Cowan  co...@cc...  http://ccil.org/~cowan
And now here I was, in a country where a right to say how the country should
be governed was restricted to six persons in each thousand of its population.
For the nine hundred and ninety-four to express dissatisfaction with the
regnant system and propose to change it, would have made the whole six
shudder as one man, it would have been so disloyal, so dishonorable, such
putrid black treason.  --Mark Twain's Connecticut Yankee