From: Philippe C. M. <phi...@sb...> - 2005-04-15 23:13:40
|
Hi, I have a few pythoncard scripts that I wish to launch from another one - ex: click on button 1 == call script 1, click on button 2 = call script 2. My code looks like below and although I do not get any error, the new wndow that appears on the click event is the same as the one from the launcher. Is there a way to achieve my goal ? Regards, Philippe class MyBackground(model.Background): def on_initialize(self, event): # if you have any initialization # including sizer setup, do it here pass #******************************************************************** def on_ID_mouseClick(self, event): import corpid app = model.Application(corpid.Corp_ID_Demo) app.MainLoop() if __name__ == '__main__': app = model.Application(MyBackground) app.MainLoop() -- ************************************* Philippe C. Martin SnakeCard, LLC www.snakecard.com +1 405 694 8098 ************************************* |