Re: [Pysparse-users] transpose operation

[Dominique O. <dom...@gm...>]

On Tue, Nov 17, 2009 at 1:24 PM, Fergus Gallagher <fe...@go...> wrote:
> On Tue, Nov 17, 2009 at 01:09:24PM -0500, Dominique Orban wrote:

>>
>> If you really need A*A^T explicitly, I suggest building A^T and then using
>> dot().
>>
>
> I think we do.  Our matrices are  ~ 10 Million square, so A^T not
> cheap doing it either explictly as A[i,j]=A[j,i] (ouch) or as
> A^T = spmatrix.dot(A,I)

OK. What I meant was to construct B=A^T to start with, instead of A.
Then you can say dot(B,B) which will give you A*A^T.

-- 
Dominique