[pyOpenSSL] 'internal error' on 0.5.1

[Yannick G. <yan...@sa...>]

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Hi,=20
  I try do customize the SafeTransport of xmlrpclib to do certificate
validation (signature and the like).  I use you SecureXMLRPCServer
from the distribution.

It works perfectly if I keep the standard SafeTransport but if I try :=20


class CustomTransport(SafeTransport):
    def make_connection(self, host):
        conn =3D SafeTransport.make_connection(self, host)
        addr =3D (conn._conn.host, conn._conn.port)
        ctx =3D SSL.Context(SSL.SSLv23_METHOD)
        ctx.set_options(SSL.OP_NO_SSLv2)
        sslConn =3D SSL.Connection( ctx, socket.socket( socket.AF_INET,=20
                                                      socket.SOCK_DGRAM) )
        sslConn.connect(addr)
        sslConn.set_connect_state()
        sslConn.renegotiate()
        sslConn.do_handshake()
        # must update the socket in conn here
        print (sslConn.get_peer_certificate())
	# do the certificate validation here
        return conn


I receive this trace :

  File "/usr/lib/python2.2/xmlrpclib.py", line 821, in __call__
    return self.__send(self.__name, args)
  File "/usr/lib/python2.2/xmlrpclib.py", line 975, in __request
    verbose=3Dself.__verbose
  File "/usr/lib/python2.2/xmlrpclib.py", line 833, in request
    h =3D self.make_connection(host)
  File "/home/ygingras/BelugaERP/belugaerp/core/client/SimpleClient.py", li=
ne=20
32, in make_connection
    sslConn.do_handshake()
SSL.Error [('SSL routines', 'SSL_clear', 'internal error')]

I'm not a SSL guru so I wonder what I may have done wrong.  Is this
the right way to make a SLL connection with pyOpenSSL ?  I use Python
2.2.2 on Red Hat 9.  OpenSSL is a custom build of 0.9.7b (I tried
M2Crypto).

Thanks for your time !

=2D --=20
Yannick Gingras
Byte Gardener, Savoir-faire Linux inc.
(514) 276-5468


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