Re: [Pyobjc-dev] Default to returning (void)?

[b.bum <bb...@ma...>]

On Feb 16, 2004, at 7:50 AM, Ronald Oussoren wrote:
> On 16-feb-04, at 16:15, Marc-Antoine Parent wrote:
>> Le 04-02-16, =E0 00:00, b.bum a =E9crit :
> I'm all for adding easy to use names instead of using selector()=20
> directly, we'll have to do that anyway if we want to use syntactic=20
> sugar later on.
>
> CVS will soon contain the functions that Bob proposed.

For once, I may have managed to beat Ronald to this.  Let's hope I got=20=

it right.

I added Accessor() to objc.   Accessor is the generic term for the=20
setters and getters in Key-Value Coding.  The Accessor() function tries=20=

to intelligently determine if it should return the setter or getter=20
signature.   I can see two problems with that:

- what if it is overriding an already existing setter/getter?  In that=20=

case, the signature should be determined by the super.

- what if the developer wants to return a scalar type?

def Accessor(func):
     """
     Return an Objective-C method object that is conformant with=20
key-value coding
     and key-value observing.
     """
     argCount =3D func.func_code.co_argcount
     if argCount is 2:
         return selector(func, signature=3D"v@:@")
     elif argCount is 1:
         return selector(func, signature=3D"@@:")
     elif argCount is 0:
         raise ValueError, "Too few arguments to function '%s'.  Cannot=20=

create selector." % foo.func_name
     else:
         raise ValueError, "Too many arguments to function '%s'.  Cannot=20=

create selector." % foo.func_name