[Pyobjc-dev] Python2.6.4, Pyobjc 2.2, Quartz, Snow Leopard

[Erik v. B. <er...@le...>]

Hi all,

I have a project in which an OSX machine renders images in response to  
http calls. It runs the python.org 2.6.4, pyobjc 2.2, twisted 9.0.0.
I can use Quartz to make a drawing context, draw simple paths, export  
as PNG. This works.

I also need to draw a couple bitmap images, so I want to use more  
functionality from Quartz. The enclosed test script works when  
executed in the terminal. Exactly the same script crashes hard when  
called as part of a twisted process.

> [eBook:trunk/lettersetter/Quartz LS Debug] erik% python /usr/bin/ 
> twistd -y twisted.quartz.test.py --pidfile quartztestpid.txt -- 
> logfile quartztest.log
> versions:
> python version: 2.6.4 (r264:75821M, Oct 27 2009, 19:48:32)
> [GCC 4.0.1 (Apple Inc. build 5493)]
> pyobjc version: 2.2
> twisted.web version: 9.0.0
>
> dry run:
> saved test image at /Users/erik/Develop/lettersetter/trunk/ 
> lettersetter/Quartz LS Debug/test.png
>
> booting twisted app
> done

Then I open a browser at http://127.0.0.1:8081/ 		kerboom!

My test script requires a png file to be nearby.
Any  help or pointers are kindly appreciated.
Erik