Re: [Pyobjc-dev] "out" parameters and return values

[Orestis M. <or...@or...>]

Hello,

I'm afraid that I don't know the answer, but it seems to me that what  
you describe should be a valid approach - I mean that it seems like  
the most reasonable syntax for this job. I assume that you've tried it  
and it doesn't work. Could you share what the output is?

Orestis
--
or...@or...
http://orestis.gr/




On 17 Feb 2009, at 19:51, Mani Ghasemlou wrote:

> Just wanted to raise this question again, as I still haven't found a  
> solution.
>
> I've posted the same question on Cocoa-dev, also with no response:
> http://www.cocoabuilder.com/archive/message/cocoa/2009/2/2/229316
>
> Would greatly appreciate any insights!
>
> Kind regards,
> Mani
>
> On Mon, Feb 2, 2009 at 9:34 AM, Mani Ghasemlou <ma...@tu...>  
> wrote:
>> Hi all,
>>
>> From what I understand of the PyObjc documentation, "out" pointer
>> variables (such as "NSError **outError") are actually appended to the
>> list of return values for a bridge function.
>>
>> For example:
>>
>> int returnIntWithError: NSError **outError
>>
>> from Python would be invoked as:
>>
>> returned_int, returned_error = returnIntWithError_(None)
>>
>> I hope that my understanding of the above is correct.
>>
>> Now, my real question is to extend the above concept to the Python
>> side, when we want to implement an informal protocol.  Let's say the
>> protocol says that I have to implement the returnIntWithError:
>> function as described above. How do I implement this function? Is the
>> code below enough?
>>
>> def returnIntWithError_(self, outError):
>>   myError = NSError.errorWithDomain_code_userInfo_('myDomain', '1',  
>> objc.nil)
>>   myReturnVal = 1
>>   return myReturnVal, myError
>>
>> Note that I am completely ignoring the "outError" parameter. Does  
>> this
>> look kosher?
>>
>> Thanks in advance for any help!
>>
>> Cheers,
>> Mani
>>
>
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