Hi Bharat,

Not exactly a Pymol question, is it? But in case you're using a list of simple vectors as tuples or lists you can easily add them the Python way, provided that the list is not too long (or it'll be slow):

vecs = [(a,b,c),(d,e,f),...]
v = [sum(i) for i in zip(vecs)]

Alternatively, you can use numpy, or use (rosetta.numeric):

import numpy
arr = numpy.array(vecs)
v = arr.sum(axis=0)

Hope it helps,

Tsjerk




On Mon, May 6, 2013 at 9:01 AM, bharat gupta <bharat.85.monu@gmail.com> wrote:
Dear Members,


I want to know that how can I store a 3d vector in to list , so that I can add them and final create a  single vector out of the list. For eg.

vec1 = ( 3.281000000000001    -0.02150000000000318     -0.572500000000001 ) + ( 3.072000000000000     0.03000000000000114     -0.934499999999999) + (3.003500000000000      0.4934999999999974      -1.14699999999999)

vec2 = (  -3.496000000000000     -0.7375000000000114     0.0164999999999970 ) + (-3.439000000000000      0.1749999999999972      0.491999999999997)  +  (-1.611000000000000      -1.171500000000002       2.75350000000000)

Finally I want to add those single vectors for each vec1 and vec2 to get two final vectors. These vectors I got from pyrosetta. When I try to append them to list I get an output like this :-

[<rosetta.numeric.__numeric_all_at_once_.xyzVector_double object at 0x0AE068A0>, <rosetta.numeric.__numeric_all_at_once_.xyzVector_double object at 0x
0AE068F0>, <rosetta.numeric.__numeric_all_at_once_.xyzVector_double object at 0x0AE06850>]

--
Bharat



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--
Tsjerk A. Wassenaar, Ph.D.