I want to open a file that I made with snoop, so:
Python 2.3.3 (#1, Feb 13 2004, 12:53:35)
[GCC 3.3.2 20031022 (Red Hat Linux 3.3.2-1)] on linux2
Type "help", "copyright", "credits" or "license" for
more information.
>>> import pcap
>>> p = pcap.pcapObject()
>>> import os
>>> os.listdir('.')
['Logica_15001.snoop', 'Logica_15002.snoop',
'Logica_15003.snoop', 'Logica_15004.snoop',
'Logica_15001.txt', 'Logica_15002.txt',
'analizaEth.py', 'Logica_15003.txt',
'Logica_15004.txt', 'gogetstats', 'parsLogSMSC.py',
'logchico.txt', 'logcmed.txt', 'SMSC.LOG;130']
>>> p.open_offline('Logica_15001.snoop')
Traceback (most recent call last):
File "<stdin>", line 1, in ?
File
"/usr/local/lib/python2.3/site-packages/pcap.py", line
57, in open_offline
def open_offline(*args): return
apply(pcapc.pcapObject_open_offline,args)
pcapc.EXCEPTION: [Errno 1] pcap_open_offline
>>>
Two things:
- It gave me an error!
- Doesn't tell me what the error is!
Thanks for all!