Roman Yakovenko wrote:
> On Wed, Sep 17, 2008 at 4:06 PM, Ken McGaugh <ke...@dn...> wrote:
>
>> Hello all,
>>
>> After reading through the archives, docs, and the source code I cannot
>> find out a way to do the following.
>>
>> Say I have a class hierarchy like this:
>>
>> class A
>> [...]
>>
>> class B : public A
>> [...]
>>
>> class C : public B
>> [...]
>>
>> I need to expose to python the classes A and C, but not B. When writing
>> the boost::python code manually I do this:
>>
>> bp::class_<C, bp::bases<A> >("C")
>>
>> So that in python it thinks that C inherits directly from A and it all
>> works. But now that I'm using Py++ I cannot figure out a way to achieve
>> the same thing and I have to expose the intermediate classes, which for
>> various reasons I really don't want to do.
>>
>> So is there a way to do what I want in Py++?
>>
>
> I am not sure. I never tested such case. Try to exclude "B" and see
> what happens.
>
When "B" is excluded then Py++ wraps the node with no bases listed
whatsoever.
> If it doesn't work I will have to tweak Py++ to support such case. It
> should not be too difficult.
>
The way I imagine it working is that Py++ would list as the base class
the first ancestor which has not been excluded.
> One possible work around is to export class "B", but without any
> members and to give it pretty ugly alias, starting with '__'.
>
Thanks, I'll give that a try. My main concern is getting the size of
the module down, and I imaging a class with no members should be fairly
light-weight.
Thanks again.
--Ken
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