Re: [Py4j-users] How to access "class"

[Peter A <pet...@gm...>]

Just tried that fix and realized I stated the question in correctly.  What
I got is a Java function like:

void stuff( Class type ) {
 ....
}

A python function which converts an int into the appropriate class.  I then
invoke Java function.

So it looks something like this in Python:

gateway.jvm.foo.Bar.stuff( lookup_type( a ) )

def lookup_type( type ):
  if type == 0:
    return THE APPROPRIATE JAVA CLASS
...

For now what I'm doing is:

if type == 0:
  obj = gateway.jvm.the.Object()

return obj,getClass()

this seems to be a bit clunky.


On Wed, Jul 15, 2015 at 8:58 PM, Alex Grönholm <ale...@ne...>
wrote:

>  The .class is a kludge to access the actual class in Java. In Python,
> simply leave out the ".class".
>
> if object.getClass() == Object:
>     # do something
>
>
> 16.07.2015, 03:18, Peter A kirjoitti:
>
>   Hi,
>
>  I need to access the static member "class" in a Java object.  For example
> in Java the code would look something like:
>
>  if( object.getClass() == Object.class ) {
>     // do something
> }
>
>  Now when I try that in py4j I run into issues that "class" is a
> protected keyword.  So the following causes it to crash:
>
> gateway.jvm.Object.class
>
>
> On the other hand gateway.jvm.Object.variable works just fine, assuming variable is a static member variable of Object.
>
> My current hack around this issue is to create a new instance of the object then call object.getClass() in python.
>
>
> Is there anyway to access "class" in python?
>
>
> - Peter
>
>
>  --
> "Now, now my good man, this is no time for making enemies."    — Voltaire
> (1694-1778), on his deathbed in response to a priest asking that he
> renounce Satan.
>
>
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-- 
"Now, now my good man, this is no time for making enemies."    — Voltaire
(1694-1778), on his deathbed in response to a priest asking that he
renounce Satan.