Re: [pure-lang-users] Numeric Arguments

[Eddie R. <er...@bm...>]

> > // mod of a double
> > x::double mod y::int = (x - intx) + (intx mod y) when intx = (int x) end;
> 
> If memory serves me, Common Lisp has this, but not any Algol-like
> language I know. I can add it to math.pure if there's enough demand.

I've had to deal with this once in Pascal somewhere before but I cant
recall. In that occasion I found that mod(double, double) may be defined
in two ways in order to stay consistent with something else ... Dang I
can't find it on google.

I don't know if you should add "double mod double" to the list or not
but I sure would hate to have to look it up again. If memory servers me
(probably doesn't) C's definition of fmod really should be called frem
instead because there is a difference between real mod and real
remainder. I guess I better shut up now before I stick my foot in my
mouth.

e.r.