phpxpath-users

Extracting XHTML Fragments

[Joseph M. F. <jos...@co...>]

Hello all.

I have, what I hope to be, a simple question.

What I am doing is extracting XHTML fragments from an XML document.  For (a very quick) example:

<?xml version="1.0"?>
<content_dictionary>
	<content_item>This is a <b>content</b> test <hr/></content_item>
</content_dictionary>

If I evaluate the XPath expression of "//content_dictionary/content_item", I recieve the following with an exportAsXML():

<content_item>This is a <b>content</b> test <hr/></content_item>

Is there any way that I can obtain the following without having to manually remove the <content_item/>?

This is a <b>content</b> test <hr/>

Any help would be greatly appreciated.  Thank you.

--Joseph

Re: Extracting XHTML Fragments

[Nigel S. <nig...@us...>]

Hi Joseph.

Sorry it took so long to reply, I moved house this last month, my PDA died,
my desktop died, and my hard drive was dying, so I'm still finding my
feet...

Sorry, no there is no easy way to do this.  The exportAsXml() wants a node,
and returns both start and end tags.  A regular expression should do the
trick though, something like:

$XmlResult2 = preg_replace("/^[^>]*>(.*)<[^<]*$/", "\\1", $XmlResult);

Cheers

Nigel

==========================================

See full example below:



<?
require_once '../XPath.class.php';
$xPath = new XPath();
$rootPath = $xPath->importFromFile('Junk.xml');

// Output what we start with.
echo "<pre>";
echo htmlspecialchars($xPath->exportAsXml());
echo "</pre>";

echo "<hr>";

// Seems to find only one node.
$aResults = $xPath->match("//content_dictionary/content_item");
print_r($aResults);

echo "<hr>";

// Seems to find only one node.
$XmlResult = $xPath->exportAsXml($aResults[0]);
print_r(htmlspecialchars($XmlResult));

echo "<hr>";

$XmlResult2 = preg_replace("/^[^>]*>(.*)<[^<]*$/", "\\1", $XmlResult);

print_r(htmlspecialchars($XmlResult2));

echo "<hr>";

// And output just for clarity
echo "<pre>";
echo htmlspecialchars($xPath->exportAsXml());
echo "</pre>";

?>