Re: php.XPath class question

[Nigel S. <nig...@us...>]

Hi Paul,

getData() takes:

string $xPathQuery
xpath to the node - resolves to *one* xpath.

So the error message is saying that "//directory[name=help]/logo" matches
more than one node (or no node).  So it doesn't know which node to return
you the data of.  Try:

 $aMatches = $xpath->match("//directory[name='help']/logo");
 print_r($aMatches);
 $logo= $xpath->getData($aMatches[0]);
 echo $logo;

(Note the ' and the call to match before the call to getData).

You might get away with:

 $logo= $xpath->getData("//directory[name='help']/logo");
 echo $logo;

Cheers

Nigel

----- Original Message -----
From: "Paul Arnold" <Pa...@pi...>
To: <nig...@us...>
Sent: Thursday, April 24, 2003 4:31 PM
Subject: php.XPath class question


Hi Nigel,

I wonder if you can help me at all.

If I try to carry out

$logo= $xpath->getData("//directory[name=help]/logo");
echo $logo;

or

$logo= $xpath->getData("//directory[@name=help]/logo");
echo $logo;

on the piece of xml below I get the following error:

XPath error in XPath.class.php:5061 The supplied xPath '' does not
*uniquely* describe a node in the xml document.

Is this correct? Is it a bug?

Can you tell me how I select the //directory[@name=help]/logo node?

<root>
    <directory name="company">
        <logo>images/logo.gif</logo>
    </directory>
    <directory name="help">
        <logo>images/logohelp.gif</logo>
    </directory>
</root>


Kind regards,

Paul Arnold

Software Engineer
Pivetal Ltd.

Tel: 023 8021 5302
Email: pa...@pi...