Hello. I have 2,4 and created automatically script but it does not work.
File: 12gzipall.php Line 1 Col 0 831 bytes 100%
<?php
// This script was created by phpMyBackupPro v.2.4 (http://www.phpMyBackupPro.net)
// In order to work probably, it must be saved in the directory /var/www/1cdeli.com.cn/public_html/phpmybackupscripts/.
$_POST['db']=array("information_schema", "1cdeli", "1cdeli2", "1cdelicopy", "1cdelitest", "1cdeliupdate", "mysql", "performance
_schema", "phpmyadmin", "postfix", "presta168", "roundcubemail", );
$_POST['comments']="Backup each call";
$_POST['tables']="on";
$_POST['data']="on";
$_POST['drop']="on";
$_POST['zip']="gzip";
$period=(3600*24)/2;
$security_key="69293398bb72519b9457ba8535e2557a";
// switch to the phpMyBackupPro v.2.4 directory
@chdir("/usr/share/phpmybackup/");
@include("backup.php");
// switch back to the directory containing this script
@chdir("/var/www/1cdeli.com.cn/public_html/phpmybackupscripts/")
?>
Even if I manually try to run this script i got this:
./12gzipall.php: line 1: ?php: No such file or directory
./12gzipall.php: line 2: syntax error near unexpected token ('
./12gzipall.php: line 2:
// This script was created by phpMyBackupPro v.2.4 (http://www.phpMyBackupPro.net)'
Could anybody help me??
Please confirm:
1) You created the php-script named 12gzipall.php, right?
2) This files starts with this lines: