[Phplib-trackers] [ phplib-Bugs-637775 ] db_mysql function free() causes warning

[<no...@so...>]

Bugs item #637775, was opened at 2002-11-13 06:00
You can respond by visiting: 
https://sourceforge.net/tracker/?func=detail&atid=403611&aid=637775&group_id=31885

Category: DB_SQL
Group: None
Status: Open
Resolution: None
Priority: 5
Submitted By: Nobody/Anonymous (nobody)
Assigned to: Nobody/Anonymous (nobody)
Summary: db_mysql function free() causes warning

Initial Comment:
When executing a second query after a query executing 
an "insert", "delete" or "update" statement using the 
same db-object, free() calls mysql_free_result() on an 
invalid resource-id.

cause: mysql_(db)_query() returns no resource_id 
but "true"/"false" on executing "insert", "delete" 
or "update" statements. query() tries to free() them.

result: php warning:
"mysql_free_result(): supplied argument is not a valid 
MySQL result resource"

(possible?) solution:
in function query():

instead of:
    # New query, discard previous result.
    if ($this->Query_ID) {
      $this->free();
    }

use:
    # New query, discard previous result.
    if ($this->Query_ID && ($this->Query_ID !==true)) {
      $this->free();
    }


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You can respond by visiting: 
https://sourceforge.net/tracker/?func=detail&atid=403611&aid=637775&group_id=31885