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Only get a blank screen

Anonymous
2003-06-20
2003-06-21
  • Anonymous

    Anonymous - 2003-06-20

    I installed program it seems to work fine, showing my databases etc. but when I cut and paste the code generated by viewmaker all I get is a blank screen. I know that it connected to database because when I don't it gives "unable to connect" error msg.
    Here is code if anyone has an idea

    ------
    <?
    include("head.php");
    include("datacon.php");
    ?>

    <?

    $queryupdate = "select * from info where id = '$id'";
    $resultupdate = MYSQL_QUERY($queryupdate);
    $numberupdate = mysql_Numrows($resultupdate);

    if ($numberupdate>0) {

    $x=0;

    ?>

    <table border=0 cellspacing=0 cellpadding=10>
    <?

            while ($x<$numberupdate)
            {

    ?>

             <tr height=30>
                <? $id=mysql_result($resultupdate,$x,"id"); ?>
    <td align=right><b>Id :</b></td>
    <td><font color=red><? echo $id; ?></td></td>
            </tr>

             <tr height=30>
                <? $username=mysql_result($resultupdate,$x,"username"); ?>
    <td align=right><b>Username :</b></td>
    <td><font color=red><? echo $username; ?></td></td>
            </tr>

             <tr height=30>
                <? $firstname=mysql_result($resultupdate,$x,"firstname"); ?>
    <td align=right><b>Firstname :</b></td>
    <td><font color=red><? echo $firstname; ?></td></td>
            </tr>

             <tr height=30>
                <? $lastname=mysql_result($resultupdate,$x,"lastname"); ?>
    <td align=right><b>Lastname :</b></td>
    <td><font color=red><? echo $lastname; ?></td></td>
            </tr>

             <tr height=30>
                <? $email=mysql_result($resultupdate,$x,"email"); ?>
    <td align=right><b>Email :</b></td>
    <td><font color=red><? echo $email; ?></td></td>
            </tr>

             <tr height=30>
                <? $city=mysql_result($resultupdate,$x,"city"); ?>
    <td align=right><b>City :</b></td>
    <td><font color=red><? echo $city; ?></td></td>
            </tr>

             <tr height=30>
                <? $state=mysql_result($resultupdate,$x,"state"); ?>
    <td align=right><b>State :</b></td>
    <td><font color=red><? echo $state; ?></td></td>
            </tr>

             <tr height=30>
                <? $country=mysql_result($resultupdate,$x,"country"); ?>
    <td align=right><b>Country :</b></td>
    <td><font color=red><? echo $country; ?></td></td>
            </tr>

             <tr height=30>
                <? $earnings=mysql_result($resultupdate,$x,"earnings"); ?>
    <td align=right><b>Earnings :</b></td>
    <td><font color=red><? echo $earnings; ?></td></td>
            </tr>

    <?

            $x++;
        } // end while
    } // end if

    ?>

    </table>

    <?
    include("foot.php");
    ?>

    ---------

    Thanks in advance

     
    • Nilesh Dosooye

      Nilesh Dosooye - 2003-06-20

      Maybe when you do the SQL Statement... it does not returns any values.... so change your code to this and see..

      $queryupdate = "select * from info where id = '$id'";
      $resultupdate = MYSQL_QUERY($queryupdate);
      $numberupdate = mysql_Numrows($resultupdate);
      if ($numberupdate==0)
      {
          echo "No Records Found !";
      }
      elseif ($numberupdate>0) {
      ....

       
    • Anonymous

      Anonymous - 2003-06-21

      change it to what you thougth and got this:

      Parse error: parse error, unexpected T_ELSE in /home/durconet/public_html/phpcode/view.php on line 14

       

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