php-java-bridge-users

[Php-java-bridge-users] Type Mismatch Exception

[<php...@li...>]

Hi,

I have instantiated a Java object in PHP 5.1.6 using the version 3.2.1b of
the php/java bridge.

I am trying to call a method (setCurrTrxDate) that expects a
java.sql.Dateparameter to be passed and I am getting the following
Java exception:

java.lang.Exception: Invoke failed:
[o(DepMnt0302AcctDispDelSrvImport$InBankParameters)]->setCurrTrxDate((Date)c(Date)).
Cause: java.lang.IllegalArgumentException: argument type mismatch
Responsible VM: 1.5.0_09


The relevant PHP code is:

        $java_date = new Java("java.sql.Date");
        $java_date->valueOf("2007-12-07");


$proxy_input->getInParameters()->getInBankParameters()->setCurrTrxDate($java_date);

I cannot understand why I am getting the type mismatch and I do not
understand the (Date)c(Date) part in the exception :-(

Any suggestions will be highly appreciated,

Apostolos

Re: [Php-java-bridge-users] Type Mismatch Exception

[<php...@li...>]

Hi,

> [o(DepMnt0302AcctDispDelSrvImport$InBankParameters)]->setCurrTrxDate((Date)c(Date)).

AFAIK you need to pass a date object. Not a class. Note the "c" above.


>         $java_date = new Java("java.sql.Date");

You cannot instanciate java.sql.Date() because no such constructor exists. You probably want 
 
 java("java.sql.Date")->valueOf(...);


For backward compatibility the JavaBridge allows the above construct, but it issues a warning on
log level 3 and above that you should correct the above code or use new JavaClass("java.sql.Date")
instead, if that's what you want.


> $java_date->valueOf("2007-12-07");

Why do you ask the date class "$java_date" to return an instance "2007-12-07" and then throw it
away?


Regards,
Jost Boekemeier



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Re: [Php-java-bridge-users] Type Mismatch Exception

[<php...@li...>]

Hi Jost,

thanks for the quick response. it works now (see below)

On 9/25/07, php...@li... <
php...@li...> wrote:

> Hi,
>
> >
> [o(DepMnt0302AcctDispDelSrvImport$InBankParameters)]->setCurrTrxDate((Date)c(Date)).
>
> AFAIK you need to pass a date object. Not a class. Note the "c" above.


So c for class and o for object (yes it is obvious now I know)




> >         $java_date = new Java("java.sql.Date");
>
> You cannot instanciate java.sql.Date() because no such constructor exists.
> You probably want
>
> java("java.sql.Date")->valueOf(...);


That did not work. I can howeever create an instance of java.sql.Date even
if no such constructor exists (bug?)





> > $java_date->valueOf("2007-12-07");
>
> Why do you ask the date class "$java_date" to return an instance
> "2007-12-07" and then throw it
> away?



That was the problem. I did not realise that I was throwing it away.
The complete code that works is:


$java_date = *new* Java("java.sql.Date");

$java_date = $java_date->valueOf("2007-12-07");

$proxy_input->getInParameters()->getInBankParameters()->setCurrTrxDate(
$java_date);



Note the

$java_date = $java_date->valueOf("2007-12-07");

instead of the line that I had originally

$java_date->valueOf("2007-12-07");

Thanks again,

Apostolos

Re: [Php-java-bridge-users] Type Mismatch Exception

[<php...@li...>]

Hi Apostolos,


> > java("java.sql.Date")->valueOf(...); 
> That did not work. 

The procedure "java" is defined in Java.inc (bridge version 4.0.0 and above) as:

  function Java($name) { 
	static $classMap = array();
	if(array_key_exists($name, $classMap)) return $classMap[$name];
	return $classMap[$name]=new JavaClass($name);
  }



> I can howeever create an instance of java.sql.Date even
> if no such constructor exists (bug?)

No, it's a feature. People used to access the class this way. It is not a good practice, but it
works and it will work in all future releases of the bridge.


When the high-level API is used (PHP 6 and PHP/Java Bridge 4.3 or above) one can access the
type in a more intuitive way:

  $date = java_sql_Date::type()->valueOf("2007-12-07");


When the new syntax is used, 

  new java_sql_Date() 

will throw a JavaException, of course.



Regards,
Jost Boekemeier



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