Hi Daniel,
> Suse Linux 10.1 is installed.
afaik there is no binary RPM available for Novell/Suse
Linux, so you need to compile from source or use the
J2EE binary instead.
> I downloaded the package from SF, installed it via
> Package Manager and moved the files into the
> extension directory.
I don't know which RPM you've installed, but the
RedHat RPM will only work on RedHat based Linux
distributions (Fedora, Centos, ...). There are other
RPM packages available for Mandrake etc.
In practice you need to move the java.so to the php
extension directory and set the java.hosts and
java.servlet (to connect to an external J2EE server)
or java.java and java.home (to start an internal Java
process).
> The php.ini contains the following values for Java:
> [Java]
> extension=java.so
This uses the default settings: it starts the
compiled, native back end which doesn't need any java
installed on the system. -- RedHat ships with gcj
("GNU Java") as the default "Java" implementation.
> What is the file "RunJavaBridge" for?
It is a Security Enhanced Linux wrapper which manages
the domain transition from http_t to javabridge_t.
It is irrelevant for you because Novell/Suse Linux
doesn't support Security Enhanced Linux. -- At the
moment only RedHat based distributions (and some
experimental Debian distributions) support Security
Enhanced Linux. Please see the SEL web page from the
NSA or RedHat for details.
> an executable, but how can I use it?
Try start RunJavaBridge, it should display a
discription.
> Any help to get the Bridge running on my system is
> appreciated.
Well, since your distribution doesn't support any
Linux specific enhancements anyway (no SEL, GNU Java,
...), you can ignore the Linux package and use the
standard J2EE package instead.
Start a Java process (for example from a service
script) as follows:
java -jar JavaBridge.jar SERVLET_LOCAL:8080
To access Java from any PHP script use the following
code:
<?
require_once("http://localhost:8080/JavaBridge/java/Java.inc");
$s = new Java("java.lang.String", "hello");
echo $s;
?>
Regards,
Jost Boekemeier
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