[Php-java-bridge-users] PHP Java Translation Help

[<php...@li...>]

Hi folks ?

This may be out of scope of the PJB project, but I?m having some =20
trouble translating Java into PHP and this is because I?m rather new =20
at Java (it?s been a trial, to say the least!).

I?m trying to figure out why a string encoding function in Java would =20
return a different value as a seemingly logical reproduction in PHP.  =20
It doesn?t make sense to me so I?m trying to see what the Java =20
function will return via PHP first, but I?m having issues.  If this =20
isn?t too off-topic, please keep reading?

1: a java application takes the string ?admin? and turns it into a =20
hash via md5 and then encodes it via base64 ? and comes up with this:

ISMvKXpXpadDiUoOSoAfww=3D=3D

2: instructions from the developers of this application write ?There =20
are 2 parts to the password, one is the hash, the second is you need =20
to Base64 encode that hash.?

3: I ran the string ?admin? through md5() and then ran that through =20
base64_encode() functions in php.  So base64_encode(md5(?admin)), =20
effectively.  I receive this value: =20
MjEyMzJmMjk3YTU3YTVhNzQzODk0YTBlNGE4MDFmYzM=3D

4: The different return values are confusing me.

5: I have grabbed code provided as an example with their application =20
and it reads like this:

    import java.io.*;
    import java.security.MessageDigest;
    import java.security.NoSuchAlgorithmException;
    import javax.mail.MessagingException;
    import javax.mail.internet.MimeUtility;

    ? other stuff snipped

    private static String encodePassword(String password) {
         MessageDigest algorithm;
         try {
             algorithm =3D MessageDigest.getInstance(ENCRYPTION_TYPE);
             algorithm.reset();
             algorithm.update(password.getBytes());
             byte[] encrypted =3D  algorithm.digest();

             ByteArrayOutputStream out =3D new ByteArrayOutputStream();
             OutputStream encoder =3D MimeUtility.encode(out, ENCODING_TYPE)=
;

             encoder.write(encrypted);
             encoder.flush();
             return new String(out.toByteArray());

         } catch (NoSuchAlgorithmException e) {
             return "Bad Encryption";
         } catch (MessagingException e) {
             return "Bad Encryption";
         } catch (IOException e) {
             return "Bad Encryption";
         }

     }

I translated this as:

$password =3D "admin";
print "encoded: ". encodePassword($password)."<br>";

function encodePassword($password) {
$message =3D new Java('java.security.MessageDigest');
$str =3D new Java('java.lang.String');

        try {
             $algorithm =3D $message->getInstance('md5');
             $reset =3D $algorithm->reset();
             $update =3D $algorithm->update($str->getBytes($password));
             //$update =3D $algorithm->update($password);
             $encrypted =3D  $algorithm->digest();

             $mu =3D new java('javax.mail.internet.MimeUtility');
             $out =3D new Java('java.io.ByteArrayOutputStream');

             $encoder =3D $mu->encode($out, 'base64');

             $encoder->write($encrypted);
             $encoder->flush();

             return $out->toByteArray();

         } catch (Exception $e) {

             print_r($e); // for debugging purposes
             return "<br>Bad Encryption";
         }
}

And I get this in response:

JavaException Object ( [message:protected] =3D> [string:private] =3D> =20
[code:protected] =3D> 0 [file:protected] =3D> =20
/usr/java/tomcat-5.5/webapps/JavaBridge/test_class.php =20
[line:protected] =3D> 25 [trace:private] =3D> Array ( [0] =3D> Array ( =20
[file] =3D> /usr/java/tomcat-5.5/webapps/JavaBridge/test_class.php =20
[line] =3D> 25 [function] =3D> __call [class] =3D> Java [type] =3D> -> [args=
] =20
=3D> Array ( [0] =3D> getBytes [1] =3D> Array ( [0] =3D> admin ) ) ) [1] =3D=
> =20
Array ( [file] =3D> =20
/usr/java/tomcat-5.5/webapps/JavaBridge/test_class.php [line] =3D> 25 =20
[function] =3D> getBytes [class] =3D> Java [type] =3D> -> [args] =3D> Array =
( =20
[0] =3D> admin ) ) [2] =3D> Array ( [file] =3D> =20
/usr/java/tomcat-5.5/webapps/JavaBridge/test_class.php [line] =3D> 17 =20
[function] =3D> encodePassword [args] =3D> Array ( [0] =3D> admin ) ) ) ) =
=20
encoded:
Bad Encryption



What I think this is telling me is that on line 25 (which is this: =20
$update =3D $algorithm->update($str->getBytes($password));) something is =20
amiss.  Line 17 is the print out the encoded password line (print =20
"encoded: ". encodePassword($password)."<br>";), which is, obviously, =20
having issues.


*Any* help as I?m trying to learn how to translate Java into PHP would =20
be smashingly appreciated.  And please advise if this is totally out =20
of bounds for this forum.


TIA,
Kate



----------------------------------------------------------------
This message was sent using IMP, the Internet Messaging Program.