Re: [Php-java-bridge-users] Fwd: PHP to java, and then back to PHP

[<php...@li...>]

Hi,

your

new $class()

is wrong. $class is a JavaObject and new $JavaObject()  requires at least
one argument.

Furthermore I'd use interfaces rather than the invocation handler:
public class Test {
  public static interface PhpObjectFactory {
    PhpObject makeObject(String t, Object[] args);
  }
  public static interface PhpObject {
    void doSomething(Object[] args);
    int getResult();
  }

  public static int runTests(PhpObjectFactory factory) throws Exception {
    PhpObject[] objects = new PhpObject[100];
    for(int i=0; i<4; i++) {
      objects[i] = factory.makeObject("ClassTest"+i, new Object[]{i});
    }

    for (int i=0; i<4; i++) {
     objects[i].doSomething(new Object[]{i});
    }

    int res=0;
    for (int i=0; i<4; i++) {
     res+=objects[i].getResult();
    }
    return res;
  }
}

<?php require_once("http://localhost:8080/JavaBridge/java/JavaBridge.inc");

class ClassTest0 {
  var $i;
  function ClassTest0 ($ar) {
   $this->i = $ar[0];
  }
  function doSomething($ar) {
   $this->i += java_values($ar[0]);
  }
  function getResult() {
   echo "result:{$this->i}\n";
   return $this->i;
  }
}
class ClassTest1 extends ClassTest0{};
class ClassTest2 extends ClassTest1{};
class ClassTest3 extends ClassTest2{};

function makeObject($tObj, $arObj) {
  $name = java_values($tObj);
  $ar = java_values($arObj);
  $obj = new $name($ar);
  return java_closure($obj, null, java('Test$PhpObject'));
}

echo java("Test")->runTests(java_closure(null, null,
java('Test$PhpObjectFactory')));
?>

javac Test.java
jar cf Test.jar *.class
java -Djava.ext.dirs=. -jar JavaBridge.jar

php -n -dallow_url_include=On test.php

=> 12


Regards,
Jost Bökemeier