Re: Replacing attribute with multiple values

[Bob G. <go...@at...>]

I believe that what you want is a reference to an array.

Like this =3D=3D
> my $result =3D $ldap->modify( $query->param("dn"),
>                             changes =3D> [
>                             replace =3D> [ \@modattrs ]    <<<<<<<<=
<<<<<<<<<<<
>                             ]
>                           );
Sorry that I haven't tested the code out, but I don't have anNet::LDA=
P
distribution on this machine, at the moment.


B
Srini Narayanappa wrote:
>=20
> Hi there,
>=20
> Can anyone show me simple example of how I can replace a multi-valu=
ed
> attribute? For example, I need the attribute "projectIndfex" to hav=
e
> the folowing values:
>=20
>   projectIndex: 1246
>   projectIndex: 9654
>   projectIndex: 88
>=20
> My code below adds only the last value in the array:
>=20
> -----------------------------------------
>=20
> @modattrs =3D ( 'projectIndex', "1246",
>               'projectIndex', "9654",
>               'projectIndex', "88"
>             );
>=20
> my $result =3D $ldap->modify( $query->param("dn"),
>                             changes =3D> [
>                             #replace =3D> [ @$modattrs ]
>                             replace =3D> [ @modattrs ]
>                             ]
>                           );
>=20
> -----------------------------------------
>=20
> Regards,
> Srini
>=20
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>=20
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