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From: Gert T. <th...@ba...> - 2002-08-15 14:50:39
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Chris, nice to read your addition to the docs. This is tough stuff so I can't comment every details at once. But I found= a=20 flaw: You say has_a forms a "one-to-one" relationship. From a objects point of = view=20 is right. But with RDBMS terms it is not. If you objects like this: publisher book has_a publisher it is a one-to-one as there is only one publisher per book but there are = books=20 for any publisher. You should explain that details because SPOPS is used as a oo wrapper aro= und a=20 RDMS. Their users could you probs to understand you. More later. Gert. |