On Fri, Nov 29, 2013 at 11:17 AM, Staffan Tylen <staffan.tylen@gmail.com> wrote:
 
I'm playing around with the date() function and am trying to convert a date in the format yyddd to yymmdd but I can't find a way to handle the yy portion of the date. The "D" option supports the ddd portion but the result shows the current year. How can I make yy be part of the calculation?

Hi Staffan,

I'm not much help here, dates are too complex for me.  If I can figure out today's date, I'm about at my limit.

My first thought though is that the DateTime class may be of more help than the date() function.

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Mark Miesfeld