Re: [ojAlgo-user] addLinearExpression java.lang.IllegalArgumentException: Must be a row vector!

[Anders P. <an...@op...>]

I have now released v30.1 that should fix that problem. /Anders

On 26 jun 2011, at 10.23, Anders Peterson wrote:

> That looks like a bug. I'll have to think about which is the correct fix.
> 
> Until I release a fixed version, creating an empty linear expression should work:
> 
> Expression tmpLinExpr = addEmptyLinearExpression("LinearExpression");
> tmpLinExpr.setLinearFactor(0, ...);
> tmpLinExpr.setLinearFactor(1, ...);
> tmpLinExpr.setLinearFactor(2, ...);
> tmpLinExpr.setLinearFactor(3, ...);
> 
> 
> /Anders
> 
> 
> 
> On 24 jun 2011, at 13.56, Luke Lindsay wrote:
> 
>> What is the correct way to create a row vector for
>> ExpressionsBasedModel.addLinearExpression?  The code below throws an
>> excecption:
>> 
>> LinearExpressionsModel model = new LinearExpressionsModel(vars);
>> Access1D a1d = Array1D.makePrimitive(2);
>> model.addLinearExpression("LinearExpression", a1d);
>> 
>> Must be a row vector!
>> java.lang.IllegalArgumentException: Must be a row vector!
>> at org.ojalgo.function.multiary.LinearFunction.<init>(LinearFunction.java:91)
>> at org.ojalgo.function.multiary.LinearFunction.makeBig(LinearFunction.java:39)
>> at org.ojalgo.optimisation.Expression.makeLinear(Expression.java:70)
>> at org.ojalgo.optimisation.ExpressionsBasedModel.addLinearExpression(ExpressionsBasedModel.java:160)
>> 
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> 
> 
> ------------------------------------------------------------------------------
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