Re: [ojAlgo-user] addLinearExpression java.lang.IllegalArgumentException: Must be a row vector!

[Anders P. <an...@op...>]

That looks like a bug. I'll have to think about which is the correct fix.

Until I release a fixed version, creating an empty linear expression should work:

Expression tmpLinExpr = addEmptyLinearExpression("LinearExpression");
tmpLinExpr.setLinearFactor(0, ...);
tmpLinExpr.setLinearFactor(1, ...);
tmpLinExpr.setLinearFactor(2, ...);
tmpLinExpr.setLinearFactor(3, ...);


/Anders



On 24 jun 2011, at 13.56, Luke Lindsay wrote:

> What is the correct way to create a row vector for
> ExpressionsBasedModel.addLinearExpression?  The code below throws an
> excecption:
> 
> LinearExpressionsModel model = new LinearExpressionsModel(vars);
> Access1D a1d = Array1D.makePrimitive(2);
> model.addLinearExpression("LinearExpression", a1d);
> 
> Must be a row vector!
> java.lang.IllegalArgumentException: Must be a row vector!
> at org.ojalgo.function.multiary.LinearFunction.<init>(LinearFunction.java:91)
> at org.ojalgo.function.multiary.LinearFunction.makeBig(LinearFunction.java:39)
> at org.ojalgo.optimisation.Expression.makeLinear(Expression.java:70)
> at org.ojalgo.optimisation.ExpressionsBasedModel.addLinearExpression(ExpressionsBasedModel.java:160)
> 
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