Hi Carlos,
On 8/27/06, Carlos Pita <car...@ya...> wrote:
>
> Hi all!
> Is there a more efficient way of creating a constant K-valued array of
> size N than:
> zeros(N) + K
> ?
>
Maybe something like this:
In [12]: a = empty((3,3), dtype=int)
In [13]: a.fill(11)
In [14]: a
Out[14]:
array([[11, 11, 11],
[11, 11, 11],
[11, 11, 11]])
I haven't timed it, so don't know how fast it is. Looking at this makes me
think fill should return the array so that one could do something like: a =
empty((3,3), dtype=int).fill(10)
Chuck
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