Re: [Numpy-discussion] numarray.where confusion

[Alok S. <as...@vi...>]

On 26/05/04: 10:43, Andrew Straw wrote:
> Todd Miller wrote:
> >On Wed, 2004-05-26 at 12:06, Francesc Alted wrote:
> >
> >>>>>a = arange(10)
> >>>>>a[(a>5) & (a<8)] = array([10, 20])
> >>>>>
> Is there an equivalently slick way to accomplish to what I'm trying 
> below?  (the the values in c[:,1] get changed based on the same-row 
> values in c[:,0]?)
> 
> from numarray import *
> a=arange(10)
> b=arange(10)+20
> c=concatenate((a[:,NewAxis],b[:,NewAxis]),axis=1)
> c[c[:,0]>7][:,1] = 0 # doesn't work because it makes a copy and 
> therefore doesn't modify c

Well, for your case, the following works:

>>> print c
[[ 0 20]
 [ 1 21]
 [ 2 22]
 [ 3 23]
 [ 4 24]
 [ 5 25]
 [ 6 26]
 [ 7 27]
 [ 8 28]
 [ 9 29]]
>>> t0 = c[:, 0]
>>> t1 = c[:, 1]
>>> t1[t0 > 7] = 0
>>> print c
[[ 0 20]
 [ 1 21]
 [ 2 22]
 [ 3 23]
 [ 4 24]
 [ 5 25]
 [ 6 26]
 [ 7 27]
 [ 8  0]
 [ 9  0]]

Not sure this helps in your real code though.

Alok

-- 
Alok Singhal (as...@vi...)          *   *          
Graduate Student, dept. of Astronomy   *           *     *
University of Virginia                                    
http://www.astro.virginia.edu/~as8ca/              *    *