From: eric j. <er...@en...> - 2002-09-13 20:44:02
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Hey Tim, Here is a short summary: Reductions and indexing return different types based on the number of dimensions of the input array: >>> b = sum(a) >>> l = len(b) # or whatever This code works happily if "a" is 2 or more dimensions, but will fail if it is 1d because the sum(a) will return a scalar in this case. To write generic code, you have to put an if/else statement in to check whether b is a scalar or an array: >>> b = sum(a) >>> if type(b) is ArrayType: ... l = len(b) ... else: ... l = 1 # or whatever you need or less verbose but still unpleasant: >>> b = asarray(sum(a)) >>> l = len(b) eric > -----Original Message----- > From: num...@li... [mailto:numpy- > dis...@li...] On Behalf Of Tim Hochberg > Sent: Friday, September 13, 2002 3:18 PM > To: num...@li... > Subject: Re: [Numpy-discussion] rank-0 arrays > > > > > [Perry wrote about Travis's proposal] > > > refresh my memory about how this proposal would work. I've heard > > proposals to add new types to Python itself, but that seems out of > > the question. Are you talking about adding new scalar types as > > module? E.g. > [snip] > > In any case, doesn't this still have the problem that Eric complained > > about, having to test for whether a result is an array or a scalar > > (which was one of the drivers to produce rank-0 results). > > Hi Perry, > > I like Travis's proposal the best of those I've seen so far, but I don't > recall the details of Eric's problem. Could you refresh us as to the > basics > of it?. > > -tim > > > > > ------------------------------------------------------- > This sf.net email is sponsored by:ThinkGeek > Welcome to geek heaven. > http://thinkgeek.com/sf > _______________________________________________ > Numpy-discussion mailing list > Num...@li... > https://lists.sourceforge.net/lists/listinfo/numpy-discussion |