Re: [Numpy-discussion] Tensor-like product with extra indices?

[Konrad H. <hi...@cn...>]

Huaiyu Zhu <hua...@ya...> writes:

> Two related questions:
> 
> 1. Suppose  B = ravel(A) and
>             B[i] corresponds to A[i0,i1,...].
> 
>    Are there named functions that map the indices
> 
>         (i0,i0,...) -> i
> 
>    and back?  This is assuming A.shape = (m0,m1,...) is known.

Untested, but the idea should work:

  def ravel_index(array, *indices):
     offsets = Numeric.multiply.accumulate(array.shape[1:][::-1])[::-1]
     return Numeric.sum(Numeric.array(indices[:-1])*offsets) + indices[-1]

> 2. Suppose the above function is called ravel_index and its
>    inverse unravel_index.
> 
>    Given a list of matrices [A0, A1, ...] is there a function that
>    calculates a matrix B such that
> 
>         B[i,j]  = A0[i0,j] * A1[i1,j] * ...
> 
>    where i = ravel_index(i0, i1, ...).

Not for all i, which I assume is what you want to do.

Konrad.
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