[Numpy-discussion] x.min() depends on ordering

[Keith G. <kwg...@gm...>]

x.min() and x.max() depend on the ordering of the elements:

>> x = M.matrix([[ M.nan, 2.0, 1.0]])
>> x.min()
nan

>> x = M.matrix([[ 1.0, 2.0, M.nan]])
>> x.min()
1.0

If I were to try the latter in ipython, I'd assume, great, min()
ignores NaNs. But then the former would be a bug in my program.

Is this related to how sort works?

>> x = M.matrix([[ M.nan, 2.0, 1.0]])
>> x.sort()
>> x
matrix([[                  nan,            1.        ,            2.        ]])

>> x = M.matrix([[ 1.0, 2.0, M.nan]])
>> x.sort()
>> x
matrix([[ 1.        ,  2.        ,         nan]])