Re: [Numpy-discussion] What does Fortran order mean?

[Lisandro D. <da...@gm...>]

On 10/16/06, Charles R Harris <cha...@gm...> wrote:
> Travis,
> I note that
> >>> a =3D arange(6).reshape(2,3,order=3D'F')
> >>> a
> array([[0, 1, 2],
>        [3, 4, 5]])
>
> Shouldn't that be 3x2? Or maybe [[0,2,4],[1,3,5]]? Reshape is making a co=
py,

Are you sure?

octave:1> a =3D 0:5
a =3D

  0  1  2  3  4  5

octave:2> reshape(a, 2, 3)
ans =3D

  0  2  4
  1  3  5



--=20
Lisandro Dalc=EDn
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