Re: [Numpy-discussion] Should numpy.sqrt(-1) return 1j rather than nan?

[Travis O. <oli...@ie...>]

David Goldsmith wrote:
> Travis Oliphant wrote:
>   
>> What could be simpler? ;-)
>>     
> Having sqrt(-1) return 1j (without having to remember that in order to 
> get this, you have to write sqrt(-1+0j) instead).
>
>   
That's exactly what scipy.sqrt(-1) does.  That was my point.

-Travis