Re: [Numpy-discussion] Should numpy.sqrt(-1) return 1j rather than nan?

[Sven S. <sve...@gm...>]

Travis Oliphant schrieb:

> 
>> If not, shouldn't
>>  
>>
>> numpy.sqrt(-1) raise a ValueError instead of returning silently nan?
>>  
>>
> This is user adjustable.  You change the error mode to raise on 
> 'invalid' instead of pass silently which is now the default.
> 
> -Travis
> 

Could you please explain how this adjustment is done, or point to the
relevant documentation.
Thank you,
Sven