Re: [Numpy-discussion] can this be made faster?

[Daniel M. <dm...@gm...>]

Thanks Bill.
Thats what I was hoping for,
but I get

>>> a
array([0, 0])
>>> b
array([0, 1, 0, 1, 0])
>>> c
array([1, 1, 1, 1, 1])
>>> a[b]+=c
Traceback (most recent call last):
  File "<stdin>", line 1, in ?
IndexError: invalid index

whereas i would like to get

array([3, 2])



On 10/8/06, Bill Baxter <wb...@gm...> wrote:
> Yes, that'd be
>    a[b] += c
>
> On 10/8/06, Daniel Mahler <dm...@gm...> wrote:
> > Is there a 'loop free' way to do this in Numeric
> >
> > for i in arange(l):
> >    a[b[i]]+=c[i]
> >
> > where l == len(b) == len(c)
> >
> > thanks
> > Daniel
>
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