Re: [Numpy-discussion] can this be made faster?

[Bill B. <wb...@gm...>]

Yes, that'd be
   a[b] += c

On 10/8/06, Daniel Mahler <dm...@gm...> wrote:
> Is there a 'loop free' way to do this in Numeric
>
> for i in arange(l):
>    a[b[i]]+=c[i]
>
> where l == len(b) == len(c)
>
> thanks
> Daniel