Re: [Numpy-discussion] dtype=object behavior change from 0.9.6 to beta 1

[Tom D. <tom...@al...>]

wrote the last email before reading your a = array([1,'A', None]) comment.
I definately agree with you on that.

On 8/31/06, Tom Denniston <tom...@al...> wrote:
>
>  Yes one can take a toy example and hack it to work but I don't
> necessarily have control over the input as to whether it is a list of object
> arrays, list of 1d heterogenous arrays, etc.  Before I didn't need to worry
> about the input because numpy understood that a list of 1d arrays is a
> 2d piece of data.  Now it understands this for all dtypes except object.  My
> question was is this new set of semantics preferable to the old.
>
> I think your example kind of proves my point.  Does it really make any
> sense for the following two ways of specifying an array give such different
> results?  They strike me as _meaning_ the same thing.  Doesn't it seem
> inconsistent to you?
>
>
> In [13]: array([array([1,'A', None], dtype=object),array([2,2,'Some
> string'],dtype=object)], dtype=object).shape
> Out[13]: (2,)
>
> and
>
> In [14]: array([array([1,'A', None], dtype=object),array([2,2,'Some
> string'],dtype=object)]).shape
> Out[14]: (2, 3)
> So my question is what is the _advantage_ of the new semantics?  The two
> examples above used to give the same results.  In what cases is it
> preferable for them to give different results?  How does it make life
> simpler?
>
>
> On 8/31/06, Charles R Harris <cha...@gm...> wrote:
>
> >  On 8/31/06, Tom Denniston <tom...@al... > wrote:
>
> > But i have hetergenious arrays that have numbers and strings and
> > NoneType, etc.
> >
> > Take for instance:
> >
> > In [11]: numpy.array([numpy.array([1,'A', None]),
> > numpy.array([2,2,'Some string'])], dtype=object)
> > Out[11]:
> > array([[1, A, None],
> >        [2, 2, Some string]], dtype=object)
> >
> > In [12]: numpy.array([ numpy.array([1,'A', None]),
> > numpy.array([2,2,'Some string'])], dtype=object).shape
> > Out[12]: (2, 3)
> >
> > Works fine in Numeric and pre beta numpy but in beta numpy versions i
> > get:
>
>
> I think you want:
>
> In [59]: a = array([array([1,'A', None],dtype=object),array([2,2,'Some
> string'],dtype=object)])
>
> In [60]: a.shape
> Out[60]: (2, 3)
>
>
> Which makes good sense to me.
>
> Chuck
>
>
>
>
>
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