Re: [Numpy-discussion] =?iso-8859-1?q?help!_type_=27float64scalar=27_?= =?iso-8859-1?q?is_not_type=09=27float=27?=

[Sebastian H. <ha...@ms...>]

On Wednesday 02 August 2006 22:43, Travis Oliphant wrote:
> Sebastian Haase wrote:
> > Thanks,
> > I just found
> > numpy.isscalar() and numpy.issctype()   ?
> > These sound like they would do what I need - what is the difference
> > between the two ?
>
> Oh, yeah.
>
> numpy.issctype works with type objects
> numpy.isscalar works with instances
>
> Neither of them distinguish between scalars and "numbers."
>
> If you get errors with isscalar it would be nice to know what they are.

I'm still trying to reproduce the exception, but here is a first comparison 
that - honestly - does not make much sense to me:
(type vs. instance seems to get mostly the same results  and why is there a 
difference with a string ('12') )

>>> N.isscalar(12) 
True
>>> N.issctype(12)
True

>>> N.isscalar('12')
True
>>> N.issctype('12')
False

>>> N.isscalar(N.array([1]))
False
>>> N.issctype(N.array([1]))
True

>>> N.isscalar(N.array([1]).dtype)
False
>>> N.issctype(N.array([1]).dtype)
False

  # apparently new 'scalars' have a dtype attribute !
>>> N.isscalar(N.array([1])[0].dtype)
False
>>> N.issctype(N.array([1])[0].dtype)
False

>>> N.isscalar(N.array([1])[0])
True
>>> N.issctype(N.array([1])[0])
True 

-Sebastian