Re: [Numpy-discussion] Selecting columns of a matrix

[Bill B. <wb...@gm...>]

On 6/21/06, Erin Sheldon <eri...@gm...> wrote:
>
> On 6/20/06, Bill Baxter <wb...@gm...> wrote:
> > I think that one's on the NumPy for Matlab users, no?
> >
> > http://www.scipy.org/NumPy_for_Matlab_Users
> >
> > >>> import numpy as num
> >  >>> a = num.arange (10).reshape(2,5)
> > >>> a
> > array([[0, 1, 2, 3, 4],
> >        [5, 6, 7, 8, 9]])
> > >>> v = num.rand(5)
> > >>> v
> > array([ 0.10934855,  0.55719644,  0.7044047 ,  0.19250088,  0.94636972])
> >  >>> num.where(v>0.5)
> > (array([1, 2, 4]),)
> > >>> a[:,num.where(v>0.5)]
> > array([[[1, 2, 4]],
> >
> >        [[6, 7, 9]]])
> >
> > Seems it grows an extra set of brackets for some reason.  Squeeze will
> get
> > rid of them.
> >
> > >>> a[:,num.where(v>0.5)].squeeze()
> > array([[1, 2, 4],
> >        [6, 7, 9]])
> >
> > Not sure why the squeeze is needed.  Maybe there's a better way.
>
> where returns a tuple of arrays.  This can have unexpected results
> so you need to grab what you want explicitly:
>
> >>> (w,) = num.where(v>0.5)
> >>> a[:,w]
> array([[1, 2, 4],
>        [6, 7, 9]])
>

Ah, yeh, that makes sense.  Thanks for the explanation.  So to turn it back
into a one-liner you just need:

>>> a[:,num.where(v>0.5)[0]]
array([[1, 2, 4],
       [6, 7, 9]])

I'll put that up on the Matlab->Numpy page.

--bb