Re: [Numpy-discussion] numpy.float64(numpy.NaN)!=numpy.NaN

[Johannes L. <a.u...@gm...>]

Hi,

> >>> numpy.float64(numpy.NaN)==numpy.NaN
>
> False
>

According to the standards, two NaNs should never be equal (since nan 
represents an 'unknown' value). So the 'real' bug is this:

------------------------
In [1]: import numpy as N

In [2]: N.nan == N.nan   # wrong result!
Out[2]: True

In [3]: N.array([N.nan]) == N.array([N.nan])   # correct result
Out[3]: array([False], dtype=bool)

In [4]: N.__version__
Out[4]: '0.9.7.2484'
------------------------

Johannes