Swap 2 words

[Davey]

Hi
I often have to swap 2 words that are not adjacent to eachother
So I wrote a little python script and figured I'd share it
(There are 2 other threads that have similar but different functionalities. see one by Dev Player and another by kadner)

This script works only with 2 selections
If the selection has a length, then the script uses those chars, otherwise, it will use the word under the cursor
After the script swaps the words, it sets a full selection on each of the 2 words swapped (just to show the actual swap)
There is an undo actions started at the beginning of the script, and ended at the end. This way, one control+z will undo the action (instead of 2)

def getWord_Sel(selNum):    # tuple of:  word, word_start, word_end
    sPos = editor.getSelectionNStart(selNum)
    ePos = editor.getSelectionNEnd(selNum)
    if sPos != ePos:
        sWrd = editor.getTextRange(sPos, ePos)
    else:
        sPos = editor.wordStartPosition(sPos, True)
        ePos = editor.wordEndPosition(sPos, True)
        sWrd = editor.getTextRange(sPos, ePos)

    return (sWrd, sPos, ePos)

def replaceWords(var1, var2):
    editor.setTarget(var2[1], var2[2])
    editor.replaceTarget(var1[0])
    editor.setTarget(var1[1], var1[2])
    editor.replaceTarget(var2[0])
    return len(var2[0]) - len(var1[0])

def setSels(var1, var2, diff):
    editor.setSelection(var1[1], var1[1]+len(var2[0]))
    editor.addSelection(var2[1]+diff, var2[1]+diff+len(var1[0]))

selsCt = editor.getSelections()
if selsCt == 2:
    editor.beginUndoAction()

    tSel1 = getWord_Sel(0)
    tSel2 = getWord_Sel(1)
    if tSel1[1] < tSel2[1]:
        sel1, sel2 = tSel1, tSel2
    else:
        sel1, sel2 = tSel2, tSel1

    diff = replaceWords(sel1, sel2)
    setSels(sel1, sel2, diff)

    editor.endUndoAction()

Hope others can find this helpful as well

Davey

[Yaron]

Hello Davey,

It took me a while to grasp your moves. :)
- When I did, I was impressed; it's beautiful.
Thank you.

Understanding "getWord_Sel(selNum)", I've realized that we both could shorten the code slightly.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
def getWord_Sel(selNum): # tuple of: word, word_start, word_end
sPos = editor.getSelectionNStart(selNum)
ePos = editor.getSelectionNEnd(selNum)

if sPos == ePos:
    sPos = editor.wordStartPosition(sPos, True)
    ePos = editor.wordEndPosition(sPos, True)

return (editor.getTextRange(sPos, ePos), sPos, ePos)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

And in Select and Find First:

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
def getExpression():
mainSel = editor.getMainSelection()
sPos = editor.getSelectionNStart(mainSel)
ePos = editor.getSelectionNEnd(mainSel)

if sPos == ePos:    # No selection.
    global oldPos
    sPos = editor.wordStartPosition(oldPos, True)
    ePos = editor.wordEndPosition(oldPos, True)
    oldPos = sPos   # For "if... flashSel()" later.

return editor.getTextRange(sPos, ePos)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Thanks again, mentor.

[Davey]

Hi Yaron
Thanks

Yes, you can shorten the code as you suggested, good work. However, I happen to prefer a little longer code that offers a little more clarity. [Being able to see return(word, position, position) makes it very clear what the function is doing.] And especially when writing for other people.

By the way, I don't mind helping as much as I can.... but I am in no way a mentor!
I simply don't know enough nor do I have enough experience (in outside languages)...
Get someone who knows more and better (like Dave...if you can!) :)

All the best
Davey

[Yaron]

Hello Davey,

Your code is indeed much clearer. Great work.

Regards.