If you do the following, the nullness inference fails unless you add an assertion:
?Foo bar = null;
bar = myMethod();
doStuff(bar);
Where
public Foo myMethod();
public void doStuff(Foo foo);
The compiler things that foo might be null, and so you can't call doStuff on it.
At least that's what I think is happening. Here's the sample code which this appeared in:
package kakuro;
import java.util.*;
import java.lang.ref.*;
public class CalculationTable<S, T>
{
private HashMap<S, ?SoftReference<T>> values = new HashMap();
private (S -> T) calculate;
public T get(S arg)
{
?SoftReference<T> valueRef = values.get(arg);
?T value;
if (valueRef == null)
{
value = calculate(arg);
}
else
{
value = valueRef.get();
}
if (value == null)
{
value = calculate(arg);
values.put(arg, new SoftReference(value));
}
return value;
}
}
The error occurs with the "new SoftReference(value)".
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Here's a greatly pared down piece of test code:
package test;
public class Test1<S, T>
{
private (S -> T) calculate;
public void bug(S arg)
{
?T value = calculate(arg);
T otherValue = id (value);
Test2<T> test2 = new Test2(value : value);
}
}
<T> T id (T arg) = arg;
public class Test2<T>
{
T value;
}
I've not determined exactly how minimal this is, but it should be pretty near. Note that the nullness inference fails for both the constructor and the assignment otherValue = id (value). Also, this does appear to have something to do with the presence of the type parameters.
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user_id=1681313
Originator: NO
And here's a minimal example (I thought I'd tested this example before, but apparently not):
package nullerror;
public void bug()
{
?String value = "";
String otherValue = value;
}