#23 doen't work on arm linux platform

[Anonymous]

Hi, i have tested netcat on arm linux platform and it
seem to doesn't work on it. it exit without any error
message and with no connection attempt.
> netcat 127.0.0.1 6600
>

[Nobody/Anonymous]

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I see the same behavior on ppc-linux. Don't have time for a
useful bug report yet.

netcat (The GNU Netcat) 0.7.1

# /root/netcat -d -v -v -v -v 127.0.0.1 2323
(debug) Trying to parse non-args parameters (argc=8, optind=6)
(debug) netcat_resolvehost(dst=0x7fffefe8, name="127.0.0.1")
(debug) netcat_inet_ntop(src=0x7fffec3c)
(debug) netcat_getport(dst=0x7ffffc98, port_string="2323",
port_num=0)
(debug) netcat_getport(dst=0x7ffffc98, port_string="(null)",
port_num=2323)
(debug) Arguments parsing complete! Total ports=-1
(debug) Main: EXIT (cleaning up)
Total received bytes: 0
Total sent bytes: 0
# echo $?
1

-Peter Jensen / diff.net

[Nobody/Anonymous]

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Had the same problem (on arm). The following line of the debug messages is interessting:

(debug) Arguments parsing complete! Total ports=-1

The result of netcat_flag_count() gets negativ. So the problem is in netcat_flag_count(). The following patch seemed to work for me:

--- netcat-0.7.1/src/flagset.c 2003-12-10 17:18:07.000000000 +0100

+++ ../netcat-0.7.1/src/flagset.c 2007-03-26 12:47:53.000000000 +0200

@@ -134,7 +134,7 @@

int netcat_flag_count(void)

{

- register char c;

+ register unsigned char c;

register int i;

int ret = 0;

@@ -154,8 +154,8 @@

Assumed that the bit number 1 is the sign, and that we will shift the

bit 1 (or the bit that takes its place later) until the the most right,

WHY it has to keep the wrong sign? */

- ret -= (c >> 7);

- c <<= 1;

+ ret += c&1;

+ c>>=1;

}

}

[Michael Chaney]

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user_id=1130656
Originator: NO

The following ARM patch works for me, too. Looks like someone wrote some very presumptious code :)