harlequin88 wrote:
> I need help... ia have to do program on I8080 platform, but i have no
> approach about it. Please if you help me i will be grateful.
>
> my problem is:
>
> Count up number of words, which count (addition) ASCII codes number (letter)
> is bigger (greather) than 200. Write up result (achievement) in decimal
> code.
>
>
> an example: Old house is big. - word house has bigger count of ASCII code
> than 200 so result will be 1.
I've never done anything with 8080 - don't think Nasm will emit code for
it - so we may not be able to help you much...
The overall approach would be something like...
get the address of your string into a register
zero a register to use as an "ascii counter"
zero a register to use as a "words over 200" counter
top:
get a character from the string into a register (8-bit)
bump the string pointer register
check if it's a zero (end of string)
yes - is the "ascii counter" over 200?
yes - bump the "words counter"
either - go to exit
no...
check if it's a space (end of word)
yes - is the "ascii counter" over 200?
yes - bump the "words counter"
zero the ascii counter
goto top
no...
add this character value to the "ascii counter"
goto top
exit:
... however you do that on whatever OS your 8080 is running
You may need an extra step in there to "print the result". I guess
that's the "decimal code" you mention? You probably do that by dividing
repeatedly by ten... the "remainders" are the digits you want to print -
add '0' to each one to "convert" it from a digit to an ascii character.
That's how you'd do it on 8086 - I assume 8080 has similar
instructions(???).
If you post what you've got so far, we *might* be able to help you debug
it, even if it isn't x86/Nasm. "Code is code", I keep sayin'...
Best,
Frank
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