Re: [Nasm-users] Please help with assembler program

[Frank K. <fbk...@zy...>]

harlequin88 wrote:
> I need help... ia have to do program on I8080 platform, but i have no
> approach about it. Please if you help me i will be grateful.
> 
> my problem is:
> 
> Count up number of words, which count (addition) ASCII codes number (letter)
> is bigger (greather) than 200. Write up result (achievement) in decimal
> code.
> 
> 
> an example: Old house is big.  - word house has bigger count of ASCII code
> than 200 so result will be 1.

I've never done anything with 8080 - don't think Nasm will emit code for 
it - so we may not be able to help you much...

The overall approach would be something like...

get the address of your string into a register
zero a register to use as an "ascii counter"
zero a register to use as a "words over 200" counter

top:
get a character from the string into a register (8-bit)
bump the string pointer register
check if it's a zero (end of string)
   yes - is the "ascii counter" over 200?
     yes - bump the "words counter"
     either - go to exit
   no...
check if it's a space (end of word)
   yes - is the "ascii counter" over 200?
     yes - bump the "words counter"
     zero the ascii counter
     goto top
   no...
     add this character value to the "ascii counter"
     goto top
exit:
   ... however you do that on whatever OS your 8080 is running

You may need an extra step in there to "print the result". I guess 
that's the "decimal code" you mention? You probably do that by dividing 
repeatedly by ten... the "remainders" are the digits you want to print - 
add '0' to each one to "convert" it from a digit to an ascii character. 
That's how you'd do it on 8086 - I assume 8080 has similar 
instructions(???).

If you post what you've got so far, we *might* be able to help you debug 
it, even if it isn't x86/Nasm. "Code is code", I keep sayin'...

Best,
Frank