#66 boolean operators don't have early exit semantics

[nasm64developer]

NASM supports the &&, ^^, and || operators, which
perform a boolean AND, XOR, and OR, respectively.

However -- unlike C -- NASM does not support early
exit semantics for those operators. For example:

%define one 1
%if ( one==1 ) || ( two==2 )
true
%else
false
%endif

This will fail because "two" hasn't been defined,
even though the "one==1" part is true, i.e. even
though the "two==2" part doesn't need evalution.

So far I believe that this behavior is acceptable
as long as it gets documented in the user manual.

[nasm64developer]

[nasm64developer]

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In my local forked version I've added support for
early exit semantics to the || and && operators.

Attached find the necessary changes and testcases.

[nasm64developer]

[nasm64developer]

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Btw, early exit semantics don't apply to the ^^ operator.

[nasm64developer]

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Originator: YES

effectively this has turned from a doc/support
request into a feature request