Re: [MLton-user] Keep MLton from being kicked out of Debian?

[Wesley W. T. <we...@te...>]

Some added security. If you don't know where objects are located, it's
harder to write exploit code.

On Fri, Nov 11, 2016 at 7:18 AM, Henry Cejtin <hen...@gm...> wrote:
> I'm curious, what is the reason for position indep. code by default in
> Debian now?
>
> On Thu, Nov 10, 2016 at 3:00 PM, Florian Weimer <fw...@de...> wrote:
>> * Matthew Fluet:
>>
>>> And, this is where I haven't figured out what Debian is trying to
>>> achieve.  Is the PIC/PIE default gcc just during package building (so
>>> that executables within .deb packages are PIE), or is it also the
>>> behavior of an installed Debian system, so that a normal user invoking
>>> gcc will get the PIC/PIE default?
>>
>> It's the latter.  GCC says:
>>
>> Configured with: […] --enable-default-pie […]
>>
>> I have verified that just running gcc with no flags produces a PIE.
>>
>>> If the behavior of an installed Debian system is not to have a
>>> PIC/PIE default gcc, then you will end up with the awkward situation
>>> where MLton will (unnecessarily) generate PIC code, although I don't
>>> think it a problem if PIC object is linked with non-PIC objects into
>>> a non-PIE executable.
>>
>> No, it's going to work just fine.  It's slightly slower than
>> necessary, but especially on amd64, the difference is minimal.
>>
>> So I think it would be fine to generate PIC code unconditionally on
>> Debian.
>>
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