From: Bill P. <pa...@ki...> - 2008-05-04 18:29:33
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On May 4, 2008, at 11:20 AM, Ken Shen wrote: > Great! Just to clarify, for example, is h_dpd = dlnP/dlnrho, and is > h_dpdt = dln(dlnP/dlnrho)/dlnT? And are these log derivatives (as > opposed > to h_dpd = dP/drho)? The helm derivatives are not logs, so h_dpd = dP/drho = dP/dd ('d' for 'density') -Bill |